0=8t^2-25t-18

Solution for 0=8t^2-25t-18 equation:

0=8t^2-25t-18

We move all terms to the left:

0-(8t^2-25t-18)=0

We add all the numbers together, and all the variables

-(8t^2-25t-18)=0

We get rid of parentheses

-8t^2+25t+18=0

a = -8; b = 25; c = +18;
Δ = b2-4ac
Δ = 252-4·(-8)·18
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1201}}{2*-8}=\frac{-25-\sqrt{1201}}{-16}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1201}}{2*-8}=\frac{-25+\sqrt{1201}}{-16}
$